Figure 6. power dissipation diagram, Figure 7. heat sink thermal resistance vs area, Lm1085 – National Instruments LM1085 Series User Manual

Page 9

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Application Note

(Continued)

must be added, one for case to heat-sink (

θ

CH

) and one for

heatsink to ambient (

θ

HA

). The junction temperature can be

predicted as follows:

T

J

= T

A

+ P

D

(

θ

JC

+

θ

CH

+

θ

HA

) = T

A

+ P

D

θ

JA

T

J

is junction temperature, T

A

is ambient temperature, and

P

D

is the power consumption of the device. Device power

consumption is calculated as follows:

I

IN

= I

L

+ I

G

P

D

= (V

IN

−V

OUT

) I

L

+ V

IN

I

G

Figure 6 shows the voltages and currents which are present
in the circuit.

Once the devices power is determined, the maximum allow-
able (

θ

JA(max)

) is calculated as:

θ

JA(max)

= T

R(max)

/P

D

= T

J(max

− T

A(max)

)/P

D

The LM1085 has different temperature specifications for two
different sections of the IC: the control section and the output
section. The Electrical Characteristics table shows the junc-
tion to case thermal resistances for each of these sections,
while the maximum junction temperatures (T

J(max)

) for each

section is listed in the Absolute Maximum section of the
datasheet. T

J(max)

is 125˚C for the control section, while

T

J(max)

is 150˚C for the output section.

θ

JA(max)

should be calculated separately for each section as

follows:
θ

JA

(max, CONTROL SECTION) = (125˚C - T

A(max)

)/P

D

θ

JA

(max, OUTPUT SECTION) = (150˚C - T

A(max)

)/P

D

The required heat sink is determined by calculating its re-
quired thermal resistance (

θ

HA(max)

).

θ

HA(max)

=

θ

JA(max)

− (

θ

JC

+

θ

CH

)

θ

HA(max)

should also be calculated twice as follows:

θ

HA(max)

=

θ

JA

(max, CONTROL SECTION) - (

θ

JC

(CON-

TROL SECTION) +

θ

CH

)

θ

HA(max)

=

θ

JA

(max, OUTPUT SECTION) - (

θ

JC

(OUTPUT

SECTION) +

θ

CH

)

If thermal compound is used,

θ

CH

can be estimated at 0.2

C/W. If the case is soldered to the heat sink, then a

θ

CH

can

be estimated as 0 C/W.

After,

θ

HA(max)

is calculated for each section, choose the

lower of the two

θ

HA(max)

values to determine the appropriate

heat sink.

If PC board copper is going to be used as a heat sink, then
Figure 7 can be used to determine the appropriate area
(size) of copper foil required.

10094716

FIGURE 6. Power Dissipation Diagram

10094764

FIGURE 7. Heat sink thermal Resistance vs Area

LM1085

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