Step 10) zero-current detection, 2 boost stage design steps, Step 11) determine boost peak current – Cirrus Logic AN379 User Manual

Page 24: An379

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AN379

24

AN379REV2

Step 10) Zero-current Detection
Zero-crossings are detected by AC coupling the drain voltage of FET Q

BUCK

to pin BUCKZCD. Capacitor C2

is sized to monitor the zero crossing of a switching drain node. Typical resonant ringing frequencies in the
CRD1680 are less than 5MHz. Implying that period T

resonant

is greater than 200ns.

Series resistor R5 is added to suppress high frequency ringing on the drain node. The RC circuit connected to
the drain of FET Q

BUCK

is required to have a time delay that is less than resonant period T

resonant

. Capacitor

C2 is 27pF and is sized to reduce power dissipation. Power loss P

C2(loss)

in capacitor C2 is calculated from

Equation 58:

where

F

SW

= nominal switching frequency equal to 175kHz

Selecting a larger capacitor will produce more losses. Resistor R5 is selected to hold the RC time constant ,



to less than period T

resonant

. Resistor R5 relationship is defined from Equation 59:

Since the typical stray capacitance on pin BUCKZCD can vary from 1pF to 3pF, resistor R5 is selected to be
6.65k

.

A resistor divider is inserted at the BUCKZCD input to limit input current I

BUCKZCD

to less than or equal to

1.5mA and reduce the zero-crossing switching signal to less than 3V. Resistor R26 is selected to be 2k

 to

avoid adding delay to RC time constant

and assist in limiting input current I

BUCKZCD

to be less than 1.5mA.

The voltage across capacitor C2 is calculated at maximum boost output voltage V

BST(max)

and is

approximately ±19V. Resistor R6 is selected to be 35.7k

.

4.2 Boost Stage Design Steps

Step 11) Determine Boost Peak Current
Assuming maximum dim is reached at 120

 and allowing for a factor of approximately 2 (k~0.5) for

second stage losses plus boost inductor current ripple.

Using Equation 24 on page 15, solve for target

power P

Target

. See Equation 60:

Using Equation 25 on page 15, calculate boost peak current I

BSTPK(max)

. See Equation 61:

where

V

rect(30



= instantaneous rectified voltage at a conduction angle of 30° and minimum input voltage

P

C2 loss

C2 V

BST

2

F

SW

27pF

28V

2

175kHz

3.7mW

=

=

=

[Eq. 58]

R5

C2

--------

200ns

27pF

-----------------

7.4k

=

=

[Eq. 59]

P

T

et

arg

P

OUT

k

--------------

180

o

dim max

-------------------------

5.15W

0.5

-----------------

180

o

120

o

------------

15.45W

=

=

=

[Eq. 60]

I

BSTPK max

P

T

et

arg

V

rect 30

o

------------------------

15.45W

7.64V

---------------------

2.0A

=

=

=

[Eq. 61]

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