Max865 compact, dual-output charge pump – Rainbow Electronics MAX865 User Manual

Page 6

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converter (RS+), where I

LOAD+

is the combination of I

V-

and the external load on V+ (I

V+

):

Determine V+ and V- as follows:

The output resistance for the positive and negative
charge pumps are tested and specified separately. The
positive charge pump is tested with V- unloaded. The
negative charge pump is tested with V+ supplied from
an external source, isolating the negative charge
pump.

Current draw from either V+ or V- is supplied by the
reservoir capacitor alone during one half cycle of the
clock. Calculate the resulting ripple voltage on either
output as follows:

where I

LOAD

is the load on either V+ or V-. For the typi-

cal f

PUMP

of 30kHz with 3.3µF reservoir capacitors, the

ripple is 25mV when I

LOAD

is 5mA. Remember that, in

most applications, the total load on V+ is the V+ load
current (I

V+

) and the current taken by the negative

charge pump (I

V-

).

Efficiency Considerations

Theoretically, a charge-pump voltage multiplier can
approach 100% power efficiency under the following
conditions:

The charge-pump switches have virtually no offset
and extremely low on-resistance.

The drive circuitry consumes minimal power.

The impedances of the reservoir and pump capaci-
tors are negligible.

For the MAX865, the energy loss per clock cycle is the
sum of the energy loss in the positive and negative
converters, as follows:

The average power loss is simply:

Resulting in an efficiency of:

MAX865

C1+

1

2

3

4

C1-

GND

3.3

µ

F

3.3

µ

F

3.3

µ

F

3.3

µ

F

3.3

µ

F

3.3

µ

F

OUT+

IN

OUT-

8

7

6

5

C2-

C2-

V-

V+

IN

GND

MAX865

C1+

1

2

3

4

C1-

8

7

6

5

C2+

C2-

V

IN

V-

V+

IN

GND

Figure 3. Paralleling MAX865s

MAX865

Compact, Dual-Output Charge Pump

6

_______________________________________________________________________________________

V

= I

x RS+ = I

+ I

x RS+

DROOP+

LOAD+

V+

V -

(

)

P

= LOSS

x f

LOSS

CYCLE

PUMP

η =

(

)

Total Output Power Total Output Power

P

LOSS

/

V

= I

(1 / f

) (1 / C

)

RIPPLE

1

2

LOAD

PUMP

RESERVOIR

V+ = 2V - V

V - = (V+ - V

) = -(2V

- V

- V

)

IN

DROOP+

DROOP

IN

DROOP+

DROOP -

LOSS

= LOSS

+ LOSS

=

C1

CYCLE

POS

NEG

1

2

1

2

V

V

V

C

V

V

IN

+

( )

+

( ) ( )





+

+

( )

( )





2

2

2

2

2

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