Field correction of calibration factor – Liquid Controls AN25 User Manual

Page 8

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Sponsler Co., Inc.

AN25 Totalizer/Rate Indicator

pg. 8

DOC#: MN-AN25



Example #5:

The Engineering Unit is pounds in 10

th

s CO

2

K-Factor = 250 pulses per gallon

Pounds of CO

2

= 8.470 per gallon

In order to establish 10

th

s, increase lbs./gal. by a factor of 10

C.F. = 84.7/250

C.F. = .3388


On the Factoring P.C.B.:

Set S6 #1 ‘ON’ (

↓ Position) ÷ 1 does not move decimal point

Set S2@3, S3@3, S4@8, S5@8

Set S1 in ‘0’ Position


If the gallons per unit volume such as 7.48 gallons per FT

3

is known, but not the unit volume per gallon as

required to calculate the calibration factor; take the reciprocal of gallons per unit volume to derive the unit
volume per gallon.

7.48 gallons per FT

3

1/7.48 = .13369 FT

3

per gallon


Example #6:

The engineering unit is ACF (FT

3

)

K-Factor = 250 pulses per gallon

ACF = .13369 per gallon

C.F. = .13369 / 250

C.F. - .0005348

On the Factoring P.C.B.:

Set S6 #4 ‘ON’ (

↓ Position) Moves decimal point right 3 places

Set S2@5, S3@3, S4@4, S5@8

Set S1 in ‘0’ Position


Example #7:

Desired Engineering Unit is ACF x 10

K-Factor = 250 pulses per gallon

ACF = .13369 per gallon

In order to establish x 10, decrease ACF/gal by a factor of 10

C.F. = .013369 / 250 = .00005348


On the factoring P.C.B.:

Set S6 #5 ‘ON’ (

↓ Position) Moves decimal point right 4 places

Set S2@5, S3@3, S4@4, S5@8 (.5348)

Set S1 in ‘0’ Position (0.5348)



Field Correction of Calibration Factor

To adjust the calibration factor to reflect the turbine’s actual response to the operating conditions, incorporate the
following formula:

New C.F =

Actual Quantity

x Present C.F.

Displayed Quantity

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