Lm358, Low power dual operational amplifiers, New prod uc t typical single-supply circuit – Diodes LM358 User Manual

Page 5: Continued) (v, Comparator with hysteresis, Ac coupled inverting amplifier, Dc coupled low-pass rc active filter

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LM358

LOW POWER DUAL OPERATIONAL AMPLIFIERS

LM358

Document number: DS35167 Rev. 2 - 2

5 of 14

www.diodes.com

February 2011

© Diodes Incorporated

NEW PROD

UC

T

Typical Single-Supply Circuit

(Continued) (V

+

=5.0V

DC

)




















































+

-

V

O

R2

10M

+V

IN

Comparator with Hysteresis

+V

REF

R1

10K

+

-

V

O

R2

10M

+V

IN

Comparator with Hysteresis

+V

REF

R1

10K

AC Coupled Inverting Amplifier

+

-

R1

10K

V

IN

+

C

IN

R

f

10K

R2

100K

R3

100K

C1

10?F

+

R

B

6.2K

R

L

10K

C

O

V

O

0

3 Vpp

AV= (As shown, A

V

=10)

R

f

R1

V

+

AC Coupled Inverting Amplifier

+

-

R1

10K

V

IN

+

C

IN

R

f

10K

R2

100K

R3

100K

C1

10?F

+

R

B

6.2K

R

L

10K

C

O

V

O

0

3 Vpp

AV= (As shown, A

V

=10)

R

f

R1

V

+

+

-

V

O

R4

1M

+V

CM

Ground Referencing a Differential

Input Signal

V

R

R1

1M

R2
1M

R3
1M

R

+

-

V

O

=V

R

+

-

V

O

R4

1M

+V

CM

Ground Referencing a Differential

Input Signal

V

R

R1

1M

R2
1M

R3
1M

R

+

-

V

O

=V

R

AC Coupled Non-Inverting Amplifier

+

-

V

IN

+

C

IN

R1

100K

C1

0.1?F

+

R

B

6.2K

R

L

10K

C

O

V

O

0

3 Vpp

R 2
1M

R3

1M

C2

10?F

R4

100K

R5

100K

V

+

A

V

=1+

R2

R1

A

V

=11(As Shown)

AC Coupled Non-Inverting Amplifier

+

-

V

IN

+

C

IN

R1

100K

C1

0.1?F

+

R

B

6.2K

R

L

10K

C

O

V

O

0

3 Vpp

R 2
1M

R3

1M

C2

10?F

R4

100K

R5

100K

V

+

A

V

=1+

R2

R1

A

V

=11(As Shown)

+

-

V

O

R4

100K

V

IN

DC Coupled Low-Pass RC Active Filter

R1

16K

R2

16K

C1

0.01?F

C2

0.01?F

R3

100K

V

O

f

O

0

f

O

= 1KHz

Q = 1
A

V

=2

+

-

V

O

R4

100K

V

IN

DC Coupled Low-Pass RC Active Filter

R1

16K

R2

16K

C1

0.01?F

C2

0.01?F

R3

100K

V

O

f

O

0

f

O

= 1KHz

Q = 1
A

V

=2

High Input Z, DC Differential Amplifier

+

-

V

O

+

-

R3

100K

R 4

100K

R2

100K

R1

100K

+V

1

+V

2

R1

R2

R4

R3

For =

(CMRR depends on this
resistor ratio match)

V

O

= (1+ )(V

2

-V

1

)

R4

R3

As Shown: V

O

= 2(V

2

-V

1

)

High Input Z, DC Differential Amplifier

+

-

V

O

+

-

R3

100K

R 4

100K

R2

100K

R1

100K

+V

1

+V

2

R1

R2

R4

R3

For =

(CMRR depends on this
resistor ratio match)

V

O

= (1+ )(V

2

-V

1

)

R4

R3

As Shown: V

O

= 2(V

2

-V

1

)

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