Scl – predictive machining, Spiral cutting length (scl) – predictive machining, Application – process flow – Sandvik Coromant Heat resistant super alloys User Manual

Page 30

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28

f

n

l

m

D

m1

Finishing
1) Select optimum insert style to suit com-

ponent/process.

2) Use optimized a

p

for that insert shape/

application choose feed
eg. CNMG 120408-SF 1105 – f

n

0.15

mm, a

p

0.25 mm.

3) Calculate SCL for component feature

eg. Dia 450 mm, l

m

= 150 mm.

4) Select cutting speed from:

CNMG 120408-SF 1105 a

p

0.25, f

n

0.15

mm’ diagram eg. v

c

= 50 m/min, see

page 30.

Spiral cutting length (SCL) – predictive machining

SCL was introduced by Sandvik Coromant
for the machining of HRSA due to the typi-
cally short tool life. One insert normally
machines one pass and is then indexed. It
is important to be able to predict for:
• Roughing – adding a stop in the program

to change the insert

• Finishing – cutting data which ensures

that the pass is completed with a predict-
able wear so as not to have to change
during the cut or recut the pass.

SCL is a method of calculating the length
of cut required for a particular feature and
then confirming with our specific recommen-
dations to ensure a reliable process.
Each SCL graph is unique and only applica-
ble for that insert, geometry, grade, depth
of cut and material. For finishing we give
you a range of cutting speeds to allow for
different length of cut requirements. For
roughing we have identified the optimum
parameters for each insert style and give
you one length.

Application – process flow

Roughing
1) Select optimum insert style to suit com-

ponent/process.

2) Use optimized v

c

, a

p

and f

n

for that

insert shape/application and note SCL
capability eg CNMX 1204A1-SM S05F
v

c

50 m/min, f

n

0.35 mm, a

p

1.7 mm.

3) Note SCL capability for that insert

SCL = 450 m, see page 30.

4) Calculate SCL for component feature

D

m1

= 450 mm, l

m

=150 mm.

5) Confirm calculated SCL with insert capa-

bilities – program required number of
insert changes
eg. 606/450 – 2 edges required.

SCL =

D

m1

x

π

x

l

m

1000

f

n

SCL =

450 x 3.14

x

150

= 606 m

1000

0.35

SCL =

450 x 3.14

x

150

= 1414 m

1000

0.15

Note. How to calculate, see page 118-119.

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