Archgard 60-1600I - Manual (Page 7)

Chalet 1600I 7
Minimum Fireplace Size
Minimum Clearances To Combustible Materials (Measured From Insert Body)
Your fireplace opening requires the following minimum sizes:
Height Width Depth From back of adjustable faceplate to front of flue collar
18 3/4”
476.25 mm)
24”
(609.6 mm)
13”
(330.2 mm)
3 1/2” — 6 1/2”
(88.9 mm — 165.1 mm)
Side Wall to Insert
= A
Top of Insert to
Bottom of Mantle (12”)
= B
Side of Insert
to Mantle Leg
= C
Hearth Extension Front
= D
Hearth Extension Side
= E
8.5”
(216 mm)
21”
(534 mm)
8.5”
(216 mm)
Canada = 18” (450 mm)
USA = 16” (400 mm)
*see note 1
Canada = 8” (200 mm)
USA = 8” (200 mm)
Note 1: If insert to floor is less than 4” the unit requires 0.5” of k = 0.84 (Btu)(in)/(Ft 2 )(hr)(°F) thermal protection.
How to determine if alternate floor protection materials are acceptable.
All floor protection must be non-combustible (i.e., metal, brick, stone, mineral fiber boards, etc.)
Any organic materials (i.e., plastics, wood paper products, etc.) are combustible and must not be used. The floor protection
specified includes some form of thermal designation such as R-value. (thermal resistance) or k-factor
(thermal conductivity).
PROCEDURE:
1. Convert specification to R-value
i. R-value given—no conversion needed. 1
ii. k-factor is given with a required thickness (T) in inches R = k x T
1
Iii. K-factor is given with a required thickness (T) in inches: R = K x 12 x T
Iv. R-factor is given with a required thickness (T) in inches: R= r x T
2. Determine the R-value of the proposed alternate floor protector.
i. Use the formula in step (1) to convert values not expressed as “R”
Ii. For multiple layers, add R-values of each layer to determine overall R-value.
3. If the overall R-value of the system is greater than the R-value of the specified floor
Protector , the alternate is acceptable.
EXAMPLE: The specified floor protector should be 3/4-inch thick material with a k-factor of 0.84. The proposed alternate is
4” brick with a r-factor of 0.2 over 1/8” mineral board with a k-factor of 0.29.
Step (a): Use formula above to convert specification to R-value.
1 1
R = k x T = 0.84 x 0.75 = 0.893
Step (b): Calculate R of proposed system.
4” brick of r = 0.2, therefore:
Mineral board = 0.29 x 0.125 = 0.431
Total = brick + mineral board = 0.8 +0.431 = 1.231 (continued on next page)
R
1
R R
R