Floor protector material calculations – Vogelzang International PB65XL User Manual

Page 15

Advertising
background image

VGZ-003 / 20120327.0

www.vogelzang.com

PB65XL /

Page 15

FLOOR PROTECTOR MATERIAL CALCULATIONS

This stove has been tested for and must be installed on a floor protector with the proper Thermal Resistance or R-value

as stated in step 1 of the installation instructions under “Locating Stove” section of this manual. If the floor protector ma-
terials listed in the instructions are not available, materials with an equivalent R-value may be substituted.

Alternate materials may be rated with C-factor (Thermal Conductance) or k-factor (Thermal Conductivity) ratings

which must be converted to R-value to determine if the alternate material meets the tested requirements. The following
instructions provide the proper information and formulas for conversion to R-value.

To determine if alternate materials are acceptable follow this sequence.
1. Convert material specifications to R-value:

a. R-value given — no conversion necessary

b. K-factor is given with a required thickness (T) in inches:

R = 1/k x T

c. C-factor is given: R = 1/C

2. Determine the R-value of proposed alternate floor protector:

a. Use formulas in step 1 above to calculate R-value of proposed material(s).
b. For multiple layers, add R-values of each layer to determine overall R-value.

3. If the overall R-value of the floor protector system is equal to or greater than the floor protector specifications given,

the alternate is acceptable.

Definitions:

Thermal conductance(C) =

BTU

=

W

(hr)(ft

2

)(°F)

(m

2

)(°K)


Thermal conductivity (k) =

(Btu)(inch)

=

W

=

Btu

(hr)(ft

2

)(°F)

(m)(°K)

(hr)(ft)(°F)

Thermal resistance (R) =

(ft

2

)(hr)(°F)

=

(m

2

)(°K)

Btu

W

Example:
The specs of floor protector material should be 3/4-inch thick material with a k-factor of 0.84.
The proposed alternative material is 4” brick with a C-factor of 1.25 over 1/8-inch mineral board
with a k-factor of 0.29.
Step 1: Convert specs to R-value.

R = 1/k x T = 1/0.84 x 0.75 = 0.893 System must have a R-value of 0.893 = Rspecs

Step 2: Calculate R-value of individual components

4” Brick with C-factor = 1.25. R = 1/C = 1/1.25 = 0.80 = Rbrick

1/8-inch (0.125”) mineral board with k-factor = 0.29. R = 1/0.29 x 0.125 = 0.431 = Rmin.brd.

Step 3: Add R-values of components to get total R-value of system

Rbrick + Rmin.brd = 0.80 + 0.431 = 1.231 = Rsystem

Step 4: Compare Rsystem to Rspecs

Rsystem = 1.231 is larger than Rspecs of 0.893. System R-value exceeds the required

specifications and therefore is an acceptable alternative.

Advertising