Lenovo IdeaCentre Q200 - Manual (Page 47)

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User Guide
5.4 Troubleshooting problems with optical drives and
hard disks
Problem: The 0ptical drive is unable to Read a CD/DVD.
Troubleshooting and problem resolution:
1. Check to determine if there is an optical drive icon in the resource manager
of the operating system. If not, restart your computer. If there is still no icon,
contact Lenovo Service. Otherwise, continue with the next step of this
procedure.
2. Confirm that the CD/DVD has been properly placed in the drive. If not, reload
the CD or DVD. Otherwise, continue with the next step of this procedure.
3. Check the specifications that came with your computer to confirm that this
optical drive is supposed to be able to read this type of CD or DVD.
4. If the CD/DVD can not be read, replace it with a known good CD/DVD such as
one that was shipped with the computer.
5. If the known good CD can not be read, visually check the operating side of the
CD/DVD for defects.
Problem: The capacity of the hard disk, as indicated by the system, is less than
the nominal capacity.
Troubleshooting and problem resolution: For computers equipped with the One-
Key Recovery feature, the system recovery feature needs to occupy some hard
disk space. This may account for the apparent hard disk capacity deficit.
Further Technical Explanation: The nominal capacity of the hard disk is
expressed in the decimal system, 1000 bytes. But the actual hard disk capacity is
expressed in the binary system as 1024 bytes. (For example, the nominal capacity
1G is 1000M, while the actual capacity 1G is 1024M).
The capacity of the hard disk shown in Windows can be calculated according to
the calculations in the following example:
The nominal capacity of the hard disk is 40G, while its actual capacity should
be: 40 x 1000 x 1000 x1000/ (1024 x 1024 x 1024) = 37G.
If the Service partition of 3G - 3 x 1000 x 1000 x 1000/ (1024 x 1024 x1024)
= 2.79G is subtracted, the capacity of the hard disk shown in the system can
be obtained.
The capacity of the hard disk as calculated using this method may be slightly
different from the actual capacity due to the rounding of totals.
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