HP 50g Graphing Calculator User Manual
Page 364
Page 11-37
Having filled up with zeros the elements of column 1 below the pivot, now we
proceed to check the pivot at position (2,2). We find that the number 3 in
position (2,3) will be a better pivot, thus, we exchange columns 2 and 3 by
using: 2#3 ‚N
@@@OK@@
Checking the pivot at position (2,2), we now find that the value of 25/8, at
position (3,2), is larger than 3. Thus, we exchange rows 2 and 3 by using:
2#3 L@RSWP
Now, we are ready to divide row 2 by the pivot 25/8, by using
³ 8/25™#2 L @RCI
Next, we eliminate the 3 from position (3,2) by using:
3\#2#3@RCIJ
Having filled with zeroes the position below the pivot, we proceed to check the
pivot at position (3,3). The current value of 2 is larger than ½ or 0, thus, we
keep it unchanged. We do divide the whole third row by 2 to convert the pivot
to 1, by using: 2Y3
@RCI
Next, we proceed to eliminate the ½ in position (1,3) by using:
1
-1/16
1/2 41/16
0
1 0
0
3
2
-1
1
0 0
0
25/8
0
-25/8
0
0 1
1
-1/16
1/2 41/16
0
1
0
0
25/8
0
-25/8
0
0
1
0
3
2
-1
1
0
0
1
-1/16 1/2
41/16
0 1 0
0
1
0
-1
0 0 1
0
3
2
-1
1 0 0
1
-1/16 1/2
41/16
0 1
0
0
1
0
-1
0 0
1
0
0
2
2
1 0
0
1
-1/16 1/2
41/16
0 1 0
0
1
0
-1
0 0 1
0
0
1
1
1 0 0