Bryant LEGACY 580J User Manual

Page 43

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43

Table 28 -- MCA/MOCP DETERMINATION NO C.O. OR UNPWRD C.O. (con’t)

UN

IT

NOM.

V---Ph---Hz

IFM

TYPE

COMBUSTION

FAN MOTOR

FLA

POWER

EXHAUST

FLA

NO C.O. or UNPWR C.O.

NO P.E.

w/ P.E. (pwrd fr/ unit)

MCA

MOCP

DISC. SIZE

MCA

MOCP

DISC. SIZE

FLA

LRA

FLA

LRA

580J

*28D

208/230---3---60

STD

0.52

5.9

129.2

175

135

584

141.0

175

148

604

MED

127.0

175

132

586

138.8

175

146

606

HIGH

133.6

175

140

622

145.4

175

153

642

MED---

High Eff

134.6

175

141

594

146.4

175

155

614

HIGH---

High Eff

147.3

175

156

668

159.1

200

169

688

460---3---60

STD

0.3

3.1

52.9

60

55

299

59.1

70

63

311

MED

51.9

60

54

300

58.1

70

61

312

HIGH

55.2

60

58

318

61.4

70

65

330

MED---

High Eff

55.7

70

59

304

61.9

80

66

316

HIGH---

High Eff

61.7

80

66

341

67.9

80

73

353

575---3---60

STD

0.24

2.4

41.1

50

43

244

45.9

60

49

252

MED

40.6

50

42

233

45.4

60

48

241

HIGH

43.3

50

46

259

48.1

60

51

267

MED---

High Eff

44.5

50

47

242

49.3

60

52

250

HIGH---

High Eff

45.0

50

47

269

49.8

60

53

277

LEGEND:

C.O.

--- Convenient outlet

DISC

--- Disconnect

FLA

--- Full load amps

IFM

--- Indoor fan motor

LRA

--- Locked rotor amps

MCA

--- Minimum circuit amps

MOCP

--- Maximum over current protection

P.E.

--- Power exhaust

UNPWRD CO

--- Unpowered convenient outlet

NOTES:

1. In compliance with NEC requirements for multimotor and

combination load equipment (refer to NEC Articles 430 and

440), the overcurrent protective device for the unit shall be fuse

or HACR breaker. Canadian units may be fuse or circuit break-

er.

2.

Unbalanced 3-Phase Supply Voltage

Never operate a motor where a phase imbalance in supply volt-

age is greater than 2%. Use the following formula to determine

the percentage of voltage imbalance.

% Voltage Imbalance

= 100 x

max voltage deviation from average voltage

average voltage

Example: Supply voltage is 230-3-60

AB = 224 v
BC = 231 v
AC = 226 v

Average Voltage =

(224 + 231 + 226)

=

681

3

3

=

227

Determine maximum deviation from average voltage.
(AB) 227 – 224 = 3 v
(BC) 231 – 227 = 4 v
(AC) 227 – 226 = 1 v

Maximum deviation is 4 v.
Determine percent of voltage imbalance.

% Voltage Imbalance

= 100 x

4

227

= 1.76%

This amount of phase imbalance is satisfactory as it is below the maxi-

mum allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is more than 2%,

contact your local electric utility company immediately.

580J

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