Bryant LEGACY 580J User Manual

Page 45

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45

Table 29 -- MCA/MOCP DETERMINATION W/ PWRD C.O. (con’t)

UN

IT

NOM.

V---Ph---Hz

IFM

TYPE

COMBUSTION

FAN MOTOR

FLA

POWER

EXHAUST

FLA

w/ PWRD C.O.

NO P.E.

w/ P.E. (pwrd fr/ unit)

MCA

MOCP

DISC. SIZE

MCA

MOCP

DISC. SIZE

FLA

LRA

FLA

LRA

580J

*28D

208/230---3---60

STD

0.52

5.9

134.0

175

140

589

145.8

175

154

609

MED

131.8

175

138

591

143.6

175

151

611

HIGH

138.4

175

145

627

150.2

175

159

647

MED---

High Eff

139.4

175

147

599

151.2

175

160

619

HIGH---

High Eff

152.1

200

161

673

163.9

200

175

693

460---3---60

STD

0.3

3.1

55.1

60

58

301

61.3

70

65

313

MED

54.1

60

57

302

60.3

70

64

314

HIGH

57.4

70

61

320

63.6

80

68

332

MED---

High Eff

57.9

70

61

306

64.1

80

68

318

HIGH---

High Eff

63.9

80

68

343

70.1

80

75

355

575---3---60

STD

0.24

2.4

42.8

50

45

246

47.6

60

50

254

MED

42.3

50

44

235

47.1

60

50

243

HIGH

45.0

50

47

261

49.8

60

53

269

MED---

High Eff

46.2

60

49

244

51.0

60

54

252

HIGH---

High Eff

46.7

60

49

271

51.5

60

55

279

LEGEND:

C.O.

--- Convenient outlet

DISC

--- Disconnect

FLA

--- Full load amps

IFM

--- Indoor fan motor

LRA

--- Locked rotor amps

MCA

--- Minimum circuit amps

MOCP

--- Maximum over current protection

P.E.

--- Power exhaust

UNPWRD CO

--- Unpowered convenient outlet

NOTES:

1. In compliance with NEC requirements for multimotor and

combination load equipment (refer to NEC Articles 430 and

440), the overcurrent protective device for the unit shall be fuse

or HACR breaker. Canadian units may be fuse or circuit break-

er.

2.

Unbalanced 3-Phase Supply Voltage

Never operate a motor where a phase imbalance in supply volt-

age is greater than 2%. Use the following formula to determine

the percentage of voltage imbalance.

% Voltage Imbalance

= 100 x

max voltage deviation from average voltage

average voltage

Example: Supply voltage is 230-3-60

AB = 224 v
BC = 231 v
AC = 226 v

Average Voltage =

(224 + 231 + 226)

=

681

3

3

=

227

Determine maximum deviation from average voltage.

(AB) 227 – 224 = 3 v
(BC) 231 – 227 = 4 v
(AC) 227 – 226 = 1 v
Maximum deviation is 4 v.
Determine percent of voltage imbalance.

% Voltage Imbalance

= 100 x

4

227

= 1.76%

This amount of phase imbalance is satisfactory as it is below the maxi-

mum allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is more than 2%,

contact your local electric utility company immediately.

580J

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