Napoleon Fireplaces GDS25P - Manual (Page 14)

14
W415-0547 / C / 07.25.06
H
1
VERTICAL TERMINATION
0 5 10 15 20
10
20
3
25 30
19
Formula 1: H
T
< 3V
T
Formula 2: H
T
+ V
T
< 40 feet
Example 4:
V
1
= 1 ft
when
(H
T
) > (V
T
)
Simple venting confi gurations
See graph to determine the required vertical rise
V
T
for the
required horizontal run
H
T
.
For vent confi gurations requiring more than one 45º and one
90° elbow , the following formulas apply:
V
2
= 1.5 ft
V
T
=
V
1
+
V
2
= 1 + 1.5 = 2.5 ft
H
1
= 6 ft
H
2
= 2 ft
H
R
=
H
1
+
H
2
= 6 + 2 = 8 ft
H
O
= .03(one 45º elbow + three 90º elbow - 135º)
= .03(45 + 90 + 90 + 90 - 135) = 5.4 ft
H
T
=
H
R
+
H
O
= 8 + 5.4 = 13.4 ft
H
T
+ V
T
= 13.4 + 2.5 = 15.9 ft
Formula 1:
H
T
< 3V
T
3V
T
= 3 x 2.5 = 7.5 ft
13.4 > 7.5
Since this formula is not met, this vent confi guration is
unacceptable.
REQUIRED
VERTICAL
R I S E I N
FEET (V
T
)
HORIZONTAL VENT RUN PLUS OFFSET IN FEET
FIGURE 11
The shaded area within the lines represents acceptable
values for H
T
and V
T
.
90°
FIGURE 12
45°
V
1
90°
V
2
90°
H
2
FIGURE 13
45°
45°
90°
90°
H
1
H
2 90° H
3
V
2
V
1
Formula 2:
H
T
+ V
T
< 40 feet
15.9 < 40
Since only formula 2 is met, this vent confi guration
is unacceptable and a new fi replace location or vent
confi guration will need to be established to satisfy both
formulas.
Example 5:
V
1
= 1.5 ft
V
2
= 8 ft
V
T
=
V
1
+
V
2
= 1.5 + 8= 9.5 ft
H
1
= 1 ft
H
2
= 1 ft
H
3
= 10.75 ft
H
R
=
H
1
+
H
2
+
H
3
= 1 + 1 + 10.75 = 12.75 ft
H
O
= .03(three 90° elbows + two 45° elbow - 135°)
= .03(90 + 90 + 90 + 45 + 45 - 135) = 6.75 ft
H
T
=
H
R
+
H
O
= 12.75 + 6.75 = 19.5 ft
H
T
+ V
T
= 19.5 + 9.5= 29 ft
Formula 1:
H
T
< 3V
T
3V
T
= 3 x 9.5 = 28.5 ft
19.5 <
28.5
Formula 2:
H
T
+ V
T
< 40 feet
29 < 40
Since both formulas are met, this vent confi guration is
acceptable.