Projection distances, 29 preparation – Panasonic TQBH9003-6 User Manual

Page 29

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29

Preparation

1.01 m(40˝)

0.61 m(2´)

0.81 m(2´8˝)

1.6 m(5´2˝)

2.0 m(6´6˝)

1.27 m(50˝)

0.76 m(2´6˝)

1.02 m(3´4˝)

2.0 m(6´6˝)

2.6 m(8´6˝)

1.52 m(60˝)

0.91 m(3´)

1.22 m(4´)

2.4 m(7´10˝)

3.1 m(10´2˝)

1.77 m(70˝)

1.07 m(3´6˝)

1.42 m(4´8˝)

2.8 m(9´2˝)

3.6 m(11´9˝)

2.03 m(80˝)

1.22 m(4´)

1.63 m(5´4˝)

3.2 m(10´5˝)

4.2 m(13´9˝)

2.28 m(90˝)

1.37 m(4´6˝)

1.83 m(6´)

3.6 m(11´9˝)

4.7 m(15´5˝)

2.54 m(100˝) 1.52 m(5´)

2.03 m(6´8˝)

4.0 m(13´1˝)

5.3 m(17´4˝)

3.81 m(150˝) 2.29 m(7´6˝)

3.05 m(10´)

6.1 m(20´)

7.9 m(25´11˝)

5.08 m(200˝) 3.05 m(10´)

4.06 m(13´4˝)

8.1 m(26´6˝)

10.6 m(34´9˝)

6.35 m(250˝) 3.81 m(12´6˝)

5.08 m(16´8˝)

10.1 m(33´1˝)

13.3 m(43´7˝)

7.62 m(300˝) 4.57 m(15´)

6.10 m(20´)

16.0 m(52´5˝)

Projection distances

Setting-up dimensions which are not given in the above table can be
calculated using the formulas below.
If the screen size (diagonal) is SD (m), then the following formula is used to
calculate the projection distance for the wide lens position (LW) and the
projection distance for the telephoto lens position (LT).

For 16:9 aspect ratios, the following formula can be used to calculate the
projection distance.

NOTE:
B The dimensions in the table above and the values obtained from the

above formulas may contain slight errors.

B If you use the projection distance for the 16:9 screen, the

4:3 projection image overflows the screen at the top and
bottom.

B If you set up the projector vertically, it may cause to

damage the projector.

B

It is recommended that you set up the projector in
a place that is tilted at less than

±35°

. Setting up

the projector in places that are tilted at more than

±35°

may cause malfunctions.

Make sure that enough space is kept for the air
outlet port.

Screen size (4:3)

Diagonal

length

Height

(SH)

Width

(SW)

Projection distance (L)

Wide

(LW)

Telephoto

(LT)

LW=0.0443xSD/0.0254-0.080

LT=0.0586xSD/0.0254-0.0774

LW=0.0407xSD/0.0254-0.080

LT=0.0538xSD/0.0254-0.0774

12.2 m(40´)

R

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