Oil iilcnii:(i'l – Carrier 48SS User Manual

Page 23

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Oil

iilcnii:(i'l

UNIT

48SS

VOLTAGE

COMPRESSOR

COND.

FAN

INDOOR

POWER SUPPLY

AWG 60 C

MAX WIRE

V-PH-HZ

RANGE

MOTOR

FAN

MIN WIRE

LENGTH

FLA

SIZEt

(ft)

Min

Max

RLA

LRA

FLA

MCA

MOCP*

0

T8

......7 6

45

‘“07*

.........

120

15

14

75

024

124

61

0 7

20

182

30

12

80

030

14 4

82

1 4

20

21 8

30

10

100

036

208/230-1-60

187

253

18 0

96

1 4

28

26 7

40

10

90

042

20 4

104

1 4

40

30 9

50

8

100

048

26 4

129

2 1

50

40 1

60

6

100

060

32 1

169

2 1

68

49 0

60

6

100

030

94

66

1 4

20

15 5

25

12

80

036

11 7

75

1 4

28

18 8

30

12

65

042

208/230-3-60

187

253

14 0

91

1 4

40

22 9

35

10

85

048

15 0

99

2 1

50

25 9

40

10

75

060

19 3

123

2 1

68

33 0

50

8

90

036

5 6

40

0 8

1 4

92

10

14

100

042
048

460-3-60

414

506

64
82

42
50

0 8

1 1

20
23

10 8
13 7

15
20

14
14

100
100

060

10 0

62

1 1

32

16 8

25

12

100

LEGEND

AWG

— American Wire Gage

FLA

— Full Load Amps

HACR

— Heating, Air Conditioning

and Refrigeration

LRA

— Locked Rotor Amps

MCA

— Minimum Circuit Amps

MOCP

— Maximum Overcurrent

Protection

NEC

— National Electrical Code

RLA

— Rated Load Amps

‘Fuse or HACR breaker
tMinimum wire size is based on 60 C copper wire If other than 60 C

wire is used, determine size from NEC Voltage drop of wire must be
less than 2% of rated voltage

NOTES:
1

In compliance with NEC requirements for multimotor and combina­

tion load equipment (refer to NEC Articles 430 and 440), the over­
current protective device for the unit shall be fuse or HACR breaker
The CSA units may be fuse or circuit breaker

2

Unbalanced 3-Phase Supply Voltage
Never operate a motor where a phase imbalance in suppiy voitage

is greater than 2% Use the following formula to determine the per­
cent voltage imbalance

% Voltage Imbalance

max voltage deviation from average voltage

Example Supply voltage is 460-3-60

AB = 452

V

BC = 464

V

AC = 455

V

Average Voltage =

452 -I- 464 + 455

1371

3

= 457

Determine maximum deviation from average voltage

(AB) 457 - 452 = 5 v
(BC) 464 - 457 =7 v
(AC) 457 - 455 =2 v

Maximum deviation is 7 v

Determine percent voltage imbalance

% Voltage Imbalance = 100 x ——

457

= 1 53%

This amount of phase imbalance is satisfactory as it is below the

maximum allowable 2%

100 x

IMPORTANT: If the supply voltage phase imbalance is more

than 2%, contact your local electric utility company immediately

average voltage

#

23

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