Bronkhorst CEM W-300B User Manual

Page 13

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BRONKHORST HIGH-TECH B.V.

By 50% r.h., the (mole) ratio between gas and water:

100

.%

.

=

sat

e

e

h

r

6

.

236

100

3

.

473

50

=

=

e

[mbar]

the moleRatio:

305

.

0

)

6

.

236

25

.

1013

(

6

.

236

=

=

X

so in a gas flow of 2 ln/min, the saturated water flow (50% r.h.) is:

61

.

0

2

305

.

0

=

=

Φ

=

Φ

gas

water

X

[ln/min]

and in [g/h]

41

.

29

]

[

4

.

22

]

[

60

]

[

18

]

[

61

.

0

ln

min

min

ln

=

mol

h

mol

g

[g/h]

At 50% r.h., the waterflow is 29.41 g/h.

(*) Assumptions: Consider water vapour as an ideal gas, 1 mole of ideal gas at normal

conditions = 22.4 l, 1 mole of water is 18 g and 1 hour is 60 min.

1 atm. = 1013.25 mbar.

9.17.082

page 13

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CEM