Installing fireplace on combustible floor, Floor protection, Warning – Martin Fireplaces 400BWBIA User Manual

Page 12

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12

61D0008

52" (400 Models)

66" (500 Models)

Safety Strip

3"x36" Min. (400 Unit)

3"x42" Min. (500 Unit)

16" Min.

(400 Unit)

20" Min.

(500 Unit)

21"

21

1

/

2

"

40

1

/

2

"

40

1

/

8

" (400 Unit)

46

1

/

8

" (500 Unit)

16"min. - 400 unit

20" min. - 500 unit

8

"

8

"

INSTALLING FIREPLACE ON COMBUSTIBLE FLOOR

(CONTINUED)

This hearth extension must be either 6" (minimum) thick stone or brick; a H1652 (400 units) or H2066 (500 units) Hearth

Extension Kit; or a locally constructed hearth that has a “K” factor less than .43 and at least ½" thick. For other non-com-

bustibles, the total thickness minimum is 1.16 times its thermal conductivity (K).

The following relations could be useful —

Minor shifting of the supporting floor or

expansion and contraction may eventually

cause a crack to develop between the hearth

extension and the face of the fireplace with

either type hearth extension. To help prevent

the cracking, firmly fasten the hearth extension

materials in place. Screw wall ties to the face of

the fireplace. Imbed the wall ties in the mortar

joints of brick, stone, or other non-combustible

materials.
Place metal safety strip packed with the

fireplace beneath the fireplace. Extend metal

safety strip under the hearth extension or into

a mortar joint of the hearth. See Figures 6

through 9. If a crack does eventually develops,

the metal safety strip will prevent sparks or

embers from falling from the fireplace onto

combustible flooring materials.

FLOOR PROTECTION

Figure 8 - Installing Hearth Extension

(Circulating Model Shown)

Figure 9 - Installing Hearth Extension and Metal Safety Strip

Only install metal safety
strip horizontal to the
fireplace.

W

ARNING

Gas

Opening

Junction

Box

Opening

Floor

Level

Fireplace

Hearth

Metal

Safety Strip

C = K divided by the material thickness
(Example C = .43 divided by 1/2 (.50)
C = .86)
K = C multiplies by the material thickness
(Example K = .86 multiplied by 1/2 (.50)
K = .43)
R = The material thickness divided by K
(Example R = 1/2 (.50) divided by .43
R = 1.16)
C = Thermal Conductant
R = Thermal Resistance

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