Liquid Controls SP4000 User Manual

Page 103

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SP4000 Flow Computer

100

After calculating the adjusted pressure and temperature, the mixture’s pressure and tempera-
ture

correlations parameters are calculated by

P = P

adj

+ 14.7

T = T

adj

.

1000

500

The compressibility factor is then calculated by first determining

m = 0.0330378T

-2

– 0.0221323

T

-3

+ 0.0161353

T

-5

n = (0.265827T

-2

+ 0.0457697

T

-4

– 0.133185

T

-1

)

m

-1

B = 3 – mn

2

9

mp

2

b =

9

n – 2mn

3

E

.

54

mp

2

2

mp

2

D = [b + (b

2

+

B

3

)

0.5

]

1/3

Where

E is a function of the pressure p and temperature T correlation parameters. The equations for E

are given in the following table for the designated regions. The following compressibility

Z

f

is deter-

mined by

Z

f

= 1

.

B / D – D + n / 3p

NX-19 Natural Gas Regions and

E Equations

Ranges

P

T

E

0 to 2

1.09 to 1.40

E

1

0 to 1.3

0.84 to 1.09

E

2

1.3 to 2.0

0.88 to 1.09

E

3

1.3 to 2.0

0.84 to 0.88

E

4

2.0 to 5.0

0.84 to 0.88

E

5

2.0 to 5.0

0.88 to 1.09

E

6

2.0 to 5.0

1.09 to 1.32

E

7

2.0 to 5.0

1.32 to 1.40

E

8

T

a

= T – 1.09

T

b

= 1.09 –

T

E

1

= 1 – 0.00075

p

2.3

exp (-20T

a

) – 0.0011

T

a

0.5

p

2

(2.17 + 1.4

T

a

0.5

p)

2

E

2

= 1 – 0.00075

p

2.3

[2 – exp (-20

T

b

)] – 1.317

T

b

4

p(1.69 – p

2

)

E

3

= 1 – 0.00075

p

2.3

[2 – exp (-20

T

b

)] + 0.455(200

T

b

6

– 0.03249

T

b

+ 2.0167

T

b

2

– 18.028

T

b

3

+ 42.844

T

b

4

)(p – 1.3)[1.69(2)

1.25

p

2

]

E

4

= 1 – 0.00075

p

2.3

[2 – exp (-20

T

b

)] + 0.455(200

T

b

6

– 0.03249

T

b

+ 2.0167

T

b

2

– 18.028

T

b

3

+ 42.844

T

b

4

)(

p – 1.3)[1.69(2)

1.25 + 80(0.88 – t)2

p

2

]

E

5

=

E

4

–X

E

6

=

E

3

–X

E

7

=

E

1

–X

E

8

=

E

7

–X

1

X = A (T – 2) + A

1

(

p – 2)

2

+

A

2

(

p – 2)

3

+

A

3

(

p – 2)

4

X

1

= (p – 1.32)

2

(

p –2)[3 – 1.483(p – 2) – 0.1(p –2)

2

+ 0.0833(

p –2)

3

]

A = 1.7172 – 2.33123T – 1.56796T

2

+ 3.47644

T

3

– 1.28603

T

4

A

1

= 0.016299 – 0.028094T – 0.48782T

2

– 0.78221

T

3

+ 0.27839

T

4

A

2

= –0.35978 + 0.51419T + 0.165453T

2

– 0.52216T

3

+ 0.19687T

4

A

3

= 0.075255 – 0.10573T – 0.058598T

2

+ 0.14416

T

3

– 0.054533

T

4

When NX-19 is used for custody transfer applications, the base compressibility factor is calculated by:

Z

b

=

(

1 + 0.00132

)

-2

T

3.25

7.3.5
Corrected
Volume Flow
Computation
(continued)

Mass Flow Computations:

mass flow = volume flow • density

Combustion Heat Flow Computations:

combustion heat flow = mass flow • combustion heating value

7.3.6
Mass Flow
Computation

7.3.7
Comb. Heat Flow
Computation

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