K factors explained, K factors explained 31 – Badger Meter Model IOG User Manual

Page 31

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K Factors Explained

The K factor (with regards to flow) is the number of pulses that must be accumulated to equal a particular volume of fluid You

can think of each pulse as representing a small fraction of the totalizing unit
An example might be a K factor of 1000 (pulses per gallon) This means that if you were counting pulses, when the count total

reached 1000, you would have accumulated 1 gallon of liquid Using the same reasoning, each individual pulse represents an

accumulation of 1/1000 of a gallon This relationship is independent of the time it takes to accumulate the counts
The frequency aspect of K factors is a little more confusing because it also involves the flow rate The same K factor number,

with a time frame added, can be converted into a flow rate If you accumulated 1000 counts (one gallon) in one minute, then

your flow rate would be 1 gpm The output frequency, in Hz, is found simply by dividing the number of counts (1000) by the

number of seconds (60) to get the output frequency
1000 ÷ 60 = 16 6666 Hz If you were looking at the pulse output on a frequency counter, an output frequency of 16 666 Hz

would be equal to 1 gpm If the frequency counter registered 33 333 Hz (2 × 16 666 Hz), then the flow rate would be 2 gpm
Finally, if the flow rate is 2 gpm, then the accumulation of 1000 counts would take place in 30 seconds because the flow rate,

and hence the speed that the 1000 counts is accumulated, is twice as great

Calculating K factors

Many styles of flow meters are capable of measuring flow in a wide range of pipe sizes Because the pipe size and volumetric

units the meter will be used on vary, it may not possible to provide a discrete K factor In the event that a discrete K factor is

not supplied then the velocity range of the meter is usually provided along with a maximum frequency output
The most basic K factor calculation requires that an accurate flow rate and the output frequency associated with that flow

rate be known

Example 1:

Known values are:

Frequency

=

700 Hz

Flow Rate

=

48 GPM

1)

700 Hz × 60 sec = 42,000 pulses per min

2)

=

=

42,000 pulses per min

K factor

48 gpm

875 pulses per gallon

Example 2:

Known values are:

Full Scale Flow Rate

=

85 gpm

Full Scale Output Frequency

=

650 Hz

1)

650 Hz × 60 sec = 39,000 pulses per min

2)

=

=

K factor 39,000 pulses per min

85 gpm

458.82 pulses per gallon

The calculation is a little more complex if velocity is used because you first must convert the velocity into a volumetric flow

rate to be able to compute a K factor
To convert a velocity into a volumetric flow, the velocity measurement and an accurate measurement of the inside diameter

of the pipe must be known Also needed is the fact that 1 US gallon of liquid is equal to 231 cubic inches

User Manual

Page 31

August 2013

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