Nortec Air Humidification System BS - Manual (Page 10)

25.05.05-A page 10 of 30
4.1.1.1 Calculating the maximum humidification capacity
The maximum humidification output is calculated by the following formulas:
with m and kg
with ft and lb
mH2O: Maximum humidification output in kg/h (lb/h)
V:
Volume of air to be humidified in m³ (ft^ 3 )
(formula: L x W x H)
V
1
: Decrease/increase in volume of air in ft^ 3 /lb
AE/h: Number of air exchange cycles per hour
The number of air exchange cycles per hour depends on the usage of the room
and must be determined by the system planner as part of the planning process.
The following guide values can be taken as the basis:
-
Textiles processing: 3 -7 AE/h
- Printing works: 2 -5 AE/h
- Warehouses: 1 - 3 AE/h
- Chilled storage: max. 1 AE/h
1.2(1.0): Fixed value for the specific weight of air in kg/m³
A:
Fixed value (7,000) for the conversation of pounds in grains in
grains/lb.
x2: Desired absolute humidity of the room air in g/kg (grains/lb)
x1: Minimum absolute humidity before humidification
in g/kg (grains/lb)
NOTES:
Where outside air represents 100 % of the air, the outside air condition in winter must be
applied. If there is an air circulation system (30 % outside air, 70 % recirculated air), the
resultant air mix must be applied.
For the values for x1, x2, x3 and V
1
refer to the psychometric chart in the appendix.
NOTES:
The formula takes no account of absorption or discharge of humidity by materials in the
humidified room.
CAUTION: This heating-up is ensures by the waste heat of machines in most cases.
SOLUTION EXAMPLE 1
In this example, a humidification capacity of 46 kg/h (101 lbs/h) is required.
In case of questions regarding the calculation of the humidification capacity, please contact NORTEC.
V x 1.2 x LW/h x (x2 – x1)
mH2O=
1,000
V x 1.0 x LW/h x (X2-X1)
mH2O=
A x V
1