Table 5 — electrical data – Carrier 48TJ016-028 User Manual
Page 13
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Table 5 — Electrical Data
UNIT
48TJ
NOMINAL
VOLTAGE
(3 Ph, 60 Hz)
VOLTAGE
RANGE
COMPRESSOR
OFM
IFM
POWER
EXHAUST
COMBUSTION
FAN MOTOR
POWER
SUPPLY
No. 1
No. 2
Min
Max
RLA
LRA
RLA
LRA
Qty
Hp
FLA (ea)
Hp
FLA
FLA
LRA
FLA
MCA
MOCP*
016
(15 Tons)
208/230
187
253
25.6
190
25.6
190
3
0.5
1.7
3.7
10.5/11.0
0.57
74/74
90/90
4,6
18.8
0.57
79/79
100/100
460
414
508
13.5
95
13.5
95
3
0.5
0.8
3.7
4.8
0.30
38
50
2.3
6.0
0.30
40
50
575
5f8
632
10.2
75
10.2
75
3
0.5
0.8
3.0
3.9
—
—
0.57
30
35
2.1
4.8
0.57
32
40
020
(18 Tons)
208/230
187
253
33
237
23
184
3
0.5
1.7
5.0
15,8/15.8
—
—
0.57
85/85
110/110
4.6
18.8
0.57
90/90
110/110
460
414
508
16.2
130
10.2
90
3
0.5
0.8
5.0
7.9
—
—
0.30
41
50
2,3
6.0
0,30
43
50
575
518
632
12.7
85
9
73
3
0.5
0.8
5.0
6,0
—
—
0.57
33
45
2,1
4.8
0.57
35
45
024
(20 Tons)
208/230
187
253
33
237
29.5
237
2
1
6.6
7.5
25.0/25.0
—
—
0.57
109/109
125/125
4,6
18.8
0.57
114/114
125/125
460
414
508
16.2
130
14.1
130
2
1
3.3
7.5
13.0
—
—
0.30
54
70
2,3
6.0
0.30
56
70
575
518
632
12.7
85
11.3
85
2
1
3.4
7.5
10.0
0.57
44
50
2.1
4.8
0.57
46
50
028
(25 Tons)
208/230
187
253
47.5
265
33
237
2
1
6.6
10.0
28.0/28.0
—
0.57
134/134
175/175
4.6
18.8
0.57
138/138
175/175
460
414
508
22.9
145
16.2
130
2
1
3.3
10.0
14.6
—
—
0.30
66
80
2.3
6.0
0.30
68
90
575
518
632
17.9
102
12.7
85
2
1
3.4
10.0
13.0
—
—
0.57
55
70
2,1
4.8
0.57
57
70
LEGEND
FLA
— Full Load Amps
HACR
— Heating, Air Conditioning and Refrigeration
!FH/l
~ Indoor (Evaporator) Fan Motor
LRA
— Locked Rotor Amps
MCA
— Minimum Circuit Amps
MOCP
— Maximum Overcurrent Protection
NEC
— National Electrical Code
OFM
— Outdoor (Condenser) Fan Motor
RLA
— Rated Load Amps
'Fuse or HACR circuit breaker.
NOTES:
1. In compliance with NEC requirements for multimofor and combinafion load
equipmenf (refer fo NEC Articles 430 and 440), the overcurrent protective
device for the unit shall be fuse or HACR breaker, Canadian units may be
fuse or circuit breaker,
2.
Unbalanced 3-Phase Supply Voltage
Never operate a motor where a phase imbalance in supply voltage Is
greater than 2%. Use the following formula to determine the percent of volt
age imbalance.
% Voltage Imbalance
max voltage deviation from average voltage
average voltage
Example: Supply voltage is 460-3-60.
ABC
AB = 452
V
BC = 464
V
AC = 455
V
Average Voltage ;
452 + 464 + 455
f37f
= 457
Determine maximum deviation from average voltage.
(AB) 457 - 452 = 5
V
(BC) 464 - 457 = 7 v
(AC) 457-455 = 2
V
Maximum deviation is 7 v.
Determine percent of voltage imbalance.
7
% Voltage Imbalance = f 00 x
457
= t .53%
This amount of phase imbalance is satisfactory as it is below the maximum
allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is more than
2%, contact your local electric utility company immediately.
t o o
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