Rice Lake FC-i/Si Series, A&D Weighing - Manual (Page 73)

Step Parameters Example 1 Example 2 Example 3
1 Ws 200kg 30.0kg 600kg
2 Ns 20,000 30,000 60,000
3 d’ 2 3 6
4 d 2 (=0.02kg) 5 (=0.005kg) 10 (=0.1kg)
Ns x d 20,000 x 2 30,000 x 5 6,000 x 1 5
1/No (=d/Ns) 1/10,000 1/6,000 1/6,000
6. Calculate the voltage sensitivity “Es”.
Es = (As-Ao) x 5,000 x 1/No (µV) [5,000 means excitation voltage 5V]
Ao: Load cell output at zero point (mV/V)
As: Load cell output at full capacity (mV/V)
7. Check the voltage sensitivity “Es”.
Es t 0.5µV Æ Calculated “Ns x d” is fixed. In example 3 in the step 5, a 600kg x
0.1kg scale will be obtained.
Es<0.5µV Æ Change “d” for new resolution 1/No.
d=1 Æ 2
d=2 Æ 5
d=5 Ж 10 Ж 1 (dividing “Ns” by 10)
In example 1,
the new d=5: 1/No=d/Ns=5/20,000=1/4,000 (200kg x 0.05kg)
In example 2,
the new d=1 and Ns=3,000: 1/No=d/Ns=1/3,000 (30kg x
0.01kg)
Using the new 1/No, go to step 6 and repeat it until Es t 0.5µV in step
7.
Remote Scale kg/lb relationship
USA Version ONLY
‰ When the capacity was set by “kg”:
Let capacity x minimum division = Ws x W d (kg)
When:
d = 1, then W d (lb) = W d (kg) x 2
d = 2, then W d (lb) = W d (kg) x 5/2
d = 5, then W d (lb) = W d (kg) x 2
And:
Ws (lb) = W d (kg) x No
Example: 15kg x 0.002kg, No = 15kg/0.002kg =7,500
W d (lb) = 0.002 x 5/2 = 0.005 (lb)
Ws (lb) = 0.005 (lb) x 7,500 = 37.5 (lb)
‰ When the capacity was set by “lb”:
Let capacity x minimum division = Ws x W d (lb)
When:
d = 1, then W d (kg) = W d (lb) x 1/2
d = 2, then W d (kg) = W d (lb) x 1/2
d = 5, then W d (kg) = W d (lb) x 2/5
And:
Ws (kg) = W d (lb) x No
Example: 30lb x 0.005lb, No = 30lb/0.005lb =6,000