Verify ct performance – Basler Electric BE1-87T User Manual

Page 79

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9171300990 Rev V

BE1-87T Installation

4-37

Step 10. Determine the CT mismatch (M

N

):

LOW TERTIARY

=

)

( (

)

=

( )

( )

=

=

MN

II

T
T

100

3
2

3
2

100

1822

7 55

6 0

2 5

100

2

0

(the smaller of the above)

(the smaller of the above)

2.41-2.40

.

.

.

.

.40

.4%

Step 11. Determine the total mismatch (M

T

):

Add the maximum CT mismatch M

N

(based on the power transformer in the neutral tap

position) to the total permissible tap excursion from neutral. In this example, a

±

10% load tap

change (LTC) must be accommodated. Therefore:

NOTE

This procedure uses the ANSI accuracy class method. See Appendix A,

Setting Note 7 for more information.

Step 12. Determine the maximum CT secondary fault current for external faults (I

F3

for three-phase, and

I

FG

for line-to-ground). Refer again to Figure 4-35 for this example. The maximum fault current is

recorded for each set of terminals for all combinations of external faults.

Verify CT Performance

HIGH

TERTIARY

LOW

Step 13. Determine the worst case burden voltage for a three-phase fault (V

B3

).

For wye-connected CTs:

)

(

3

3

R

L

F

B

R

R

I

V

+

=

For delta-connected CTs, based on a three-phase fault (refer to Appendix A, Setting Note 2):

)

R

3

R

3

R

(

I

V

R

L

3

F

3

B

+

+

=

W

Where:

I

F3

= determined in Step 12 R

R

= relay resistance in ohms (< 0.05 ohm)

R

W

= winding burden

R

L

= one-way lead resistance in ohms

Neglecting R

R

, use R

L

from Figure 4-35:

HIGH LOW

=

(

)

)

=

=

=

M

I

I

T

T

N

100

100

6 04
7 55

2 0
2 5

100

0 80

0%

1
3

1
3

(the smaller of the above)

0.80- 0.80

.
.

.
.

.

(

(the smaller of the above)

(

)

) (

HIGH TERTIARY

=

=

=

=

M

I

I

T

T

N

100

100

18 22

6 04

6 0
2 0

100

3 0

0 6%

2
1

2

1

(the smaller of the above)

3.02-3.0

.

.

.
.

.

.

(

)

) (

(

)

) (

(the smaller of the above)

M

M

T

N

=

+ LTC

M

T

=

+

=

0 6 10 10 6 %

.

.

IF3

3360

120

=
= 28 A

IF3

13

600

=
=

,280

22 A

IF3

8400

240

=
= 35 A

IFG

=
=

3375

120

28 A

IFG

=
=

9000

240

38 A

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