Burkert Type 8056 - Manual (Page 24)

- 24 - RS232_485_ETP_MODBUS_BU_REV02.doc
3.3.9. EXAMPLE OF ETP COMAND
Reading model and software version of the converter:
mnemonic: MODSV
syntax of the command: “MODSV?”
list of the bytes and corresponding values of the command:
byte 0: address to = chr(0)
byte 1: address from = chr(170)
byte 2: block code = chr(90) (length of the next data block smaller than 250 characters)
byte 3: length = chr(7) (length of the next data block)
byte 4: block data = chr(77) = ‘M’
byte 5: block data = chr(79) = ‘O’
byte 6: block data = chr(68) = ‘D’
byte 7: block data = chr(83) = ‘S’
byte 8: block data = chr(86) = ‘V’
byte 9: block data = chr(63) = ‘?’
byte 10: carriage-return <CR> = chr(13)
byte 11: checksum =
chr(239)
List of the bytes to send to the converter in hexadecimal format:
chr(0x00) + chr(0xAA) + chr(0x5A) + chr(0x08) + chr(0x4D) + chr(0x4F) + chr(0x44) + chr(0x53) +
chr(0x56) + chr(0x3F) + chr(0x0D) + chr(0xEF)
3.3.10. EXAMPLE OF RESPONSE FOR PRECECDENT ETP COMAND
Header string response:
byte 0 = chr(170)
byte 1 = chr(0)
byte 2 = chr(218) 218 dec = 0xDA hex (code 218 = length of the next data block smaller than 250 characters)
byte 3 = chr(29) number of characters of the data block = 29 bytes
Body string response:
byte 4 = 77 chr(77) = ‘M’ char 1
byte 5 = 76 chr(76) = ‘L’ char 2
byte 6 = 32 chr(32) = ‘ ’ char 3
byte 7 = 50 chr(50) = ‘2’ char 4
byte 8 = 49 chr(49) = ‘1’ char 5
byte 9 = 48 chr(48) = ‘0’ char 6
byte 10 = 32 chr(32) = ‘ ’ char 7
byte 11 = 86 chr(86) = ‘V’ char 8
byte 12 = 69 chr(69) = ‘E’ char 9
byte 13 = 82 chr(82) = ‘R’ char 10
byte 14 = 46 chr(46) = ‘.’ char 11
byte 15 = 51 chr(51) = ‘3’ char 12
byte 16 = 46 chr(46) = ‘.’ char 13
byte 17 = 54 chr(54) = ‘6’ char 14
byte 18 = 48 chr(48) = ‘0’ char 15
byte 19 = 32 chr(32) = ‘ ’ char 16
byte 20 = 77 chr(77) = ‘M’ char 17
byte 21 = 97 chr(97) = ‘a’ char 18
byte 22 = 121 chr(121) = ‘y’ char 19