Grass Valley NV9000-SE v.5.0 User Manual
Page 469

451
NV9000-SE Utilities
User’s Guide
Consider the 4-partition system again. This time, N
AB
= 3, N
BC
= 2, and N
CD
= 4:
Then
(1-hop)
AB = (5 x 2) x 3 = 30
BC = (2 x 5) x 2 = 20
CD = (5 x 2) x 4 = 40
(2-hop)
AC = (AB)(AC) / 2 =
AC
= 30 x 20 / 2 = 600 / 2 = 300
BD = (BC)(CD) / 5 =
BD
= 20 x 40 / 5 = 800 / 5 = 160
(3-hop)
AD = (AB)(BC)(CD) / (d
B
x d
C
) =
AD
= 30 x 20 x 40 / (2 x 5) = 24,000 / 10 = 2400
All Paths
30 + 20 + 40 + 300 + 160 + 2400 = 2950.
(Again, the figure is a maximum, because if you omit certain signal types from certain paths, the
number of paths decreases. The calculations for that situation are not worth the trouble.)
Your tieline configuration will probably be more complex than the examples given here.
Complex configurations can be decomposed into simpler parts and the two formulas (given
under
on page 447) can then be applied.
A
(HD)
d = 5
C
(HD)
d = 5
B
(SD)
d = 2
D
(SD)
d = 2
3
2
4