Reference, Pressure loss – Yokogawa digitalYEWFLO (DY) User Manual

Page 128

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<13. GENERAL SPECIFICATIONS>

13-18

IM 01F06A00-01EN

Reference

Table 13.11 Inner Diameter and Nominal value

Model Code

Inner

Diameter

mm

Nominal

K-Factor

Pulse/L

Nominal Pulse

Rate

Hz / m/s Hz / m

3

/h

DY015

DY025

/R1

DY040

/R2

14.6

376

62.7

104

DY025

DY040

/R1

DY050

/R2

25.7

68.6

35.5

19.1

DY040

DY050

/R1

DY080

/R2

39.7

18.7

23.1

5.19

DY050

DY080

/R1

DY100

/R2

51.1

8.95

18.3

2.49

DY080

DY100

/R1

DY150

/R2

71.0

3.33

13.2

0.925

DY100

DY150

/R1

DY200

/R2

93.8

1.43

9.88

0.397

DY150

DY200

/R1

—

138.8

0.441

6.67

0.123

DY200

—

—

185.6

0.185

5.00

0.0514

DY250

—

—

230.8

0.0966

4.04

0.0268

DY300

—

—

276.2

0.0563

3.37

0.0156

DY400

—

—

354.2

0.0265

2.61

0.00736

Pressure Loss

Calculation of pressure loss for standard type

obtained from the following equations.

P=108Ч10

−5

Ч

f

×

2

······ (1)

or
P=135×

f

×

Q

f

2

D

4

········· (2)

where,

P: Pressure loss (kPa )

f

: Density at operating condition (kg/m

3

)

: Flow velocity (m/s)
Q

f

: Actual

fl ow rate (m

3

/h)

D: Inner diameter of digitalYEWFLO (mm)

(Example)
DY050, hot water: 80°C, fl owrate: 30 m

3

/h

1. Since the density of water at 80°C is 972 kg/

m

3

, substitute this value in equation (2):

P = 135 Ч 972 Ч 30

2

/ 51.1

4

= 17.3 kPa

2. Obtain the pressure loss using equation (1).

The fl ow velocity when the fl ow rate is 30 m

3

/h

is given by:

 =

354×Q

f

/D

2

=

354×30

51.1

2

= 4.07m/s

Therefore, substitute this value in equation (1):
P = 108 Ч 10

-5

Ч 972 Ч 4.07

2

= 17.3 kPa

Calculation of pressure loss for reduced bore
type (Option code: /R1)
obtained from the following equations.
P = 124 Ч 10

-5

Ч

f

×

2

··········· (3)

or
P = 155 ×

ρ

f

× Q

f

2

/ D

4

············ (4)

(Example)
DY040/R1, hot water: 50 °C, fl owrate: 10 m

3

/h

1. Since the density of water at 50 °C is 992 kg/

m

3

, substitute this value in equation (4):

P = 155 Ч 992 Ч 10

2

/ 25.7

4

= 35.3 kPa

2. Obtain by using equation (3). The fl ow velocity

when the fl ow rate is 10 m

3

/h is given by:

= 354 × Q

f

× /D

2

= 354 Ч 10 Ч 25.7

2

=

5.4m/s

Therefore, substitute this value in equation (3):
P = 124 Ч 10

-5

Ч 992 Ч 5.4

2

= 35.3 kPa

Calculation of pressure loss for reduced bore
type (Option code: /R2)
obtained from the following equations.
P = 138 Ч 10

-5

Ч

f

×

2

··········· (5)

or
P = 173 × 

f

×

Q

f

2

D

4

················ (6)

(Example)
DY050-/R2, hot water: 50 °C, fl owrate: 15 m

3

/h

1. Since the density of water at 50 °C is 992 kg/

m

3

, substitute this value in equation (6):

P = 173 Ч 992 Ч 15

2

/ 25.7

4

= 88.5 kPa

2. Obtain by using equation (5). The fl ow velocity

when the fl ow rate is 15m

3

/h is given by:

 =

354×Q

f

/D

2

=

354×15

25.7

2

= 8.0m/s

Therefore, substitute this value in equation (5):
P = 138 Ч 10

-5

Ч 992 Ч 8.0

2

= 88.5 kPa

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