Reference, Pressure loss – Yokogawa digitalYEWFLO (DY) User Manual

Page 128

Advertising
background image

<13. GENERAL SPECIFICATIONS>

13-18

IM 01F06A00-01EN

Reference

Table 13.11 Inner Diameter and Nominal value

Model Code

Inner

Diameter

mm

Nominal

K-Factor

Pulse/L

Nominal Pulse

Rate

Hz / m/s Hz / m

3

/h

DY015

DY025

/R1

DY040

/R2

14.6

376

62.7

104

DY025

DY040

/R1

DY050

/R2

25.7

68.6

35.5

19.1

DY040

DY050

/R1

DY080

/R2

39.7

18.7

23.1

5.19

DY050

DY080

/R1

DY100

/R2

51.1

8.95

18.3

2.49

DY080

DY100

/R1

DY150

/R2

71.0

3.33

13.2

0.925

DY100

DY150

/R1

DY200

/R2

93.8

1.43

9.88

0.397

DY150

DY200

/R1

138.8

0.441

6.67

0.123

DY200

185.6

0.185

5.00

0.0514

DY250

230.8

0.0966

4.04

0.0268

DY300

276.2

0.0563

3.37

0.0156

DY400

354.2

0.0265

2.61

0.00736

Pressure Loss

Calculation of pressure loss for standard type

obtained from the following equations.

P=108Ч10

−5

Ч

f

×

2

······ (1)

or
P=135×

f

×

Q

f

2

D

4

········· (2)

where,

P: Pressure loss (kPa )

f

: Density at operating condition (kg/m

3

)

: Flow velocity (m/s)
Q

f

: Actual

fl ow rate (m

3

/h)

D: Inner diameter of digitalYEWFLO (mm)

(Example)
DY050, hot water: 80°C, fl owrate: 30 m

3

/h

1. Since the density of water at 80°C is 972 kg/

m

3

, substitute this value in equation (2):

P = 135 Ч 972 Ч 30

2

/ 51.1

4

= 17.3 kPa

2. Obtain the pressure loss using equation (1).

The fl ow velocity when the fl ow rate is 30 m

3

/h

is given by:

 =

354×Q

f

/D

2

=

354×30

51.1

2

= 4.07m/s

Therefore, substitute this value in equation (1):
P = 108 Ч 10

-5

Ч 972 Ч 4.07

2

= 17.3 kPa

Calculation of pressure loss for reduced bore
type (Option code: /R1)
obtained from the following equations.
P = 124 Ч 10

-5

Ч

f

×

2

··········· (3)

or
P = 155 ×

ρ

f

× Q

f

2

/ D

4

············ (4)

(Example)
DY040/R1, hot water: 50 °C, fl owrate: 10 m

3

/h

1. Since the density of water at 50 °C is 992 kg/

m

3

, substitute this value in equation (4):

P = 155 Ч 992 Ч 10

2

/ 25.7

4

= 35.3 kPa

2. Obtain by using equation (3). The fl ow velocity

when the fl ow rate is 10 m

3

/h is given by:

= 354 × Q

f

× /D

2

= 354 Ч 10 Ч 25.7

2

=

5.4m/s

Therefore, substitute this value in equation (3):
P = 124 Ч 10

-5

Ч 992 Ч 5.4

2

= 35.3 kPa

Calculation of pressure loss for reduced bore
type (Option code: /R2)
obtained from the following equations.
P = 138 Ч 10

-5

Ч

f

×

2

··········· (5)

or
P = 173 × 

f

×

Q

f

2

D

4

················ (6)

(Example)
DY050-/R2, hot water: 50 °C, fl owrate: 15 m

3

/h

1. Since the density of water at 50 °C is 992 kg/

m

3

, substitute this value in equation (6):

P = 173 Ч 992 Ч 15

2

/ 25.7

4

= 88.5 kPa

2. Obtain by using equation (5). The fl ow velocity

when the fl ow rate is 15m

3

/h is given by:

 =

354×Q

f

/D

2

=

354×15

25.7

2

= 8.0m/s

Therefore, substitute this value in equation (5):
P = 138 Ч 10

-5

Ч 992 Ч 8.0

2

= 88.5 kPa

Advertising