Rockwell Automation 2097-Vxxx Kinetix 350 Single-axis EtherNet/IP Servo Drive User Manual - Manual (Page 21)

Rockwell Automation Publication 2097-UM002A-EN-P - December 2013 21
Install the Kinetix 350 Drive System Chapter 2
Enclosure Selection
This example is provided to assist you in sizing an enclosure for your
Bulletin 2097 drive system. You need heat dissipation data from all components
planned for your enclosure to calculate the enclosure size. See Power Dissipation
Specifications on
page 23 for your drive.
With no active method of heat dissipation (such as fans or air conditioning)
either of the following approximate equations can be used.
If the maximum ambient rating of the Kinetix 350 drive system is 40 °C (104 °F)
and if the maximum environmental temperature is 20 °C (68 °F), then T=20. In
this example, the total heat dissipation is 416 W (sum of all components in
enclosure). So, in the equation below, T=20 and Q=416.
In this example, the enclosure must have an exterior surface of at least 4.53 m
2
. If
any portion of the enclosure is not able to transfer heat, do not include heat in the
calculation.
Because the minimum cabinet depth to house the Kinetix 350 system (selected
for this example) is 332 mm (13 in.), the cabinet needs to be approximately 2000
x 700 x 332 mm (78.7 x 27.6 x 13.0 in.) HxWxD.
2 x (0.332 x 0.70) + 2 x (0.332 x 2.0) + 2 x (0.70 x 2.0) = 4.59 m
2
Because this cabinet size is considerably larger than what is necessary to house the
system components, it can be more efficient to provide a means of cooling in a
smaller cabinet. Contact your cabinet manufacturer for options available to cool
your cabinet.
Metric Standard English
Where T is temperature difference between inside air and
outside ambient (°C), Q is heat generated in enclosure
(Watts), and A is enclosure surface area (m
2 ). The exterior
surface of all six sides of an enclosure is calculated as
Where T is temperature difference between inside air and
outside ambient (°F), Q is heat generated in enclosure
(Watts), and A is enclosure surface area (ft
2) . The exterior
surface of all six sides of an enclosure is calculated as
A = 2dw + 2dh + 2wh A = (2dw + 2dh + 2wh) /144
Where d (depth), w (width), and h (height) are in meters. Where d (depth), w (width), and h (height) are in inches.
A = 0.38Q
1.8T - 1.1
A = 4.08Q
T - 1.1
A = 0.38 (416)
1.8 (20) - 1.1
= 4.53 m 2