5 negative sequence current accuracy, Negative sequence current accuracy -5 – GE 489 User Manual

Page 217

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GE Multilin

489 Generator Management Relay

7-5

7 TESTING

7.2 HARDWARE FUNCTIONAL TESTS

7

7.2.5 NEGATIVE SEQUENCE CURRENT ACCURACY

The 489 measures negative sequence current as a percent of Full Load Amperes (FLA). A sample calculation of negative
sequence current is shown below. Given the following generator parameters:

Rated MVA (P

A

) = 1.04

Voltage Phase to Phase (V

pp

): 600 V

we have:

(EQ 7.1)

With the following output currents:

(EQ 7.2)

The negative-sequence current Ins is calculated as:

(EQ 7.3)

Therefore, the negative sequence current is 14% of FLA. The specification for negative sequence current accuracy is per
output current inputs. Perform the steps below to verify accuracy.

1.

Alter the following setpoints:

S2 SYSTEM SETUP

ÖØ

GENERATOR PARAMETER

Ö

GENERATOR RATED MVA: "

1.04"

S2 SYSTEM SETUP

ÖØ

GENERATOR PARAMETER

ÖØ

VOLTAGE PHASE-PHASE:

"600"

(Note: This is equivalent to setting FLA = 1000 A – For testing purposes ONLY!)

S2 SYSTEM SETUP

Ö

CURRENT SENSING

Ö

PHASE CT PRIMARY:

"1000 A"

2.

Inject the values shown in the table below and verify accuracy of the measured values. View the measured values in:

A2 METERING DATA

Ö

CURRENT METERING

INJECTED CURRENT

EXPECTED NEGATIVE SEQUENCE

CURRENT LEVEL

MEASURED NEGATIVE SEQUENCE

CURRENT LEVEL

1 A UNIT

5 A UNIT

Ia = 0.78 A

∠0°

Ib = 1 A

∠113° lag

Ic = 1 A

∠247° lag

Ia = 3.9 A

∠0°

Ib = 5 A

∠113° lag

Ic = 5 A

∠247° lag

14% FLA

Ia = 1.56 A

∠0°

Ib = 2 A

∠113° lag

Ic = 2 A

∠247° lag

Ia = 7.8 A

∠0°

Ib = 10 A

∠113° lag

Ic = 10 A

∠247° lag

28% FLA

Ia = 0.39 A

∠0°

Ib = 0.5 A

∠113° lag

Ic = 0.5 A

∠247° lag

Ia = 1.95 A

∠0°

Ib = 2.5 A

∠113° lag

Ic = 2.5 A

∠247° lag

7% FLA

FLA

P

A

3 V

pp

Ч

-----------------------

1.04 10

6

Ч

3 600

Ч

---------------------------

1000 A

=

=

=

I

a

780 0

°, I

b

1000 113

° lag, I

c

1000 247

° lag

=

=

=

I

ns

1
3

--- I

a

a

2

I

b

aI

c

+

+

(

) where a

1 120

°

0.5

j0.866

+

=

=

=

1
3

--- 780 0°

1 120

°

(

)

2

1000

113

°

(

)

1 120

°

(

) 1000 113°

(

)

+

+

(

)

=

1
3

--- 780 0°

1000 127

°

1000 233

°

+

+

(

)

1
3

--- 780 601.8

j798.6 601.8

j798.6

+

(

)

=

=

141.2

=

%I

ns

I

ns

FLA

----------- 100

Ч

14%

=

=

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