1 calculations, 7applications – Lenze DSD User Manual

Page 163

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Lenze · Drive Solution Designer · Manual · DMS 4.2 EN · 12/2013 · TD23

163

7

Applications

7.15

Synchronous drive of squeegees

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _

7.15.1

Calculations

For a synchronous drive with squeegees according to the drawing, the following applies:

Conditions
The differential force always has to be smaller than the static friction to prevent slippage. The

coefficient S provides for a safety reserve that can be individually adapted to the application.
For a reliable power transmission from the drive roll to the material the following condition has to

be met. Otherwise a warning appears.

[7-153] Equation 1: Differential force

Contact pressure
The lower roll W

1

ist mounted rigidly. The upper roll W

2

is pressed against roll W

1

with the contact

pressing force F. The contact pressing force F consists of the force due to weight F

W2

and an addi-

tionally acting force F

add

(e.g. by a pneumatic cylinder).

The proportion of the force due to weight F

W2

depends on the mounting position (angle of tilt β) of

the roll pair W

1

, W

2

, with regard to the vertical.

[7-154] Equation 2: Contact pressing force

Stationary torque
The stationary torque for the lower roll W

1

(drive roll) is calculated as follows:

[7-155] Equation 3: Stationary torque

Friction torque
The friction of the roll bearings is usually specified by the efficiency η

Brg

. Since the friction torque is

a constant torque, a friction torque M

μ

is calculated by means of the efficiency and the maximum

stationary torque, which is considered as a constant torque.

• The direction of the friction torque is always opposed to the direction of movement and is math-

ematically expressed by the fraction v/|v|.

[7-156] Equation 4: Friction torque

F

in

F

out

F μ

0

1

S

100

---------

<

F F

W2

F

add

+

=

F m

W2

g cosβ

⋅ ⋅

F

add

+

=

M

sds

f

1

f

2

+

(

)

F

1000

------------- v

v

-----

F

in

F

out

(

)

+

d

1000 2

---------------------

=

M

μ

1

η

Brg

----------

1

 max M

sds

(

) vv-----

=

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