3 calculations, Calculations, 7applications – Lenze DSD User Manual

Page 76

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7

Applications

7.3

Belt drive, rotating

76

Lenze · Drive Solution Designer · Manual · DMS 4.2 EN · 12/2013 · TD23

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7.3.3

Calculations

For a linear axis with rotating toothed belts according to the drawing, the following applies:
The belt pulley has the following effective diameter, where p

Cog

specifies the belt pitch:

[7-10] Equation 1: Diameter of belt pulley

Conversion of translatory variables into rotary variables

[7-11] Equation 2: Angle

[7-12] Equation 3: Angular velocity

[7-13] Equation 4: Angular acceleration

Forces of the linear motion
First the mass which is to be moved linearly has to be calculated. The payload m

L

can adopt different

values during the travel cycle. The mass of carriage m

aux

is considered separately.

[7-14] Equation 5: Total mass

The friction force F

μ

can for instance occur on the guide rails of the slide. The force acts opposite to

the direction of movement and is taken into consideration by the fraction v/|v| in the following

equation, where at v = 0 the force F

μis

0. The static friction at standstill is not considered.

[7-15] Equation 6: Friction force

If the friction force F

μ

is related to the mass in motion, a specific travelling resistance results, which

contains all parts depending on the mass:

[7-16] Equation 7: Specific travelling resistance of the application

For vehicles with a wheel guide instead of a linear guide, here the travelling resistance F’ is to be

used:

d

Cog

[mm]

p

Cog

[mm] N

Cog

π

-------------------------------------------

=

ϕ

2000 s

d

Cog

--------------------

2000 π s

⋅ ⋅

p

Cog

N

Cog

----------------------------

=

=

ω

2000 v

d

Cog

--------------------

2000 π v

⋅ ⋅

p

Cog

N

Cog

----------------------------

=

=

α

2000 a

d

Cog

--------------------

2000 π a

⋅ ⋅

p

Cog

N

Cog

----------------------------

=

=

m

sum

m

L

m

aux

+

=

F

μ

m

sum

g μ

Gdn

β

cos

v

v

-----

⋅ ⋅

=

F’

g μ

Gdn

β

cos

=

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