7applications – Lenze DSD User Manual

Page 77

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Lenze · Drive Solution Designer · Manual · DMS 4.2 EN · 12/2013 · TD23

77

7

Applications

7.3

Belt drive, rotating

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _

[7-17] Equation 8: Specific travelling resistance of the application for vehicles with a wheel guide

Additionally a counterforce F

vs

opposite to the positive direction of movement and a component of

the force due to weight (downhill force) caused by the slope β can act. Constant friction forces of the

guide rails, which are independent of the mass, have to be taken into consideration with the correct

sign in F

vs

.

[7-18] Equation 9: Total translatory force

Required torque of the application
The required torque of the application M

App

has to be calculated in three steps. First the force that

is transmitted via the toothed belt has to be ascertained.

• The mass m

Blt

of the toothed belt is considered by the specific mass m’

Blt

and the length l

Blt

.

[7-19] Equation 10: Force of the slide

For calculating the torque, the mass inertia of the application is required. It has to be divided into

two types:

A. An additional mass inertia on the belt pulley of the toothed belt is added to the mass inertia of

the belt pulley:

[7-20] Equation 11: Mass inertia on the side of the belt pulley

B. Additional mass inertias that are connected via the toothed belts and rotate at the same speed

(e.g. deflection pulleys, belt tighteners), are included in the moment of inertia J

aux

of the deflec-

tion pulleys:

[7-21] Equation 12: Mass inertia of the deflection pulleys

Now the required torque at the drive can be calculated:

[7-22] Equation 13: Required torque at the drive

The constant torque loss which occurs within the belt is determined under full load from the torque

at the drive with the efficiency in motor mode of the prestressed belt:

F’

g 2 f

β

cos

⋅ ⋅

d

Whl

---------------------------

d

Brg

μ

Brg

d

Whl

-------------------------- μ

Gdn

+

+

=

F

sum

F

vs

m

sum

g

+

β

sin

=

F

aux

F’ m

sum

v

v

-----

F

sum

+

m

sum

l

Blt

m’

Blt

+

(

)

+

a

=

J

Cog

J

n const

=

J

k

k 1

=

n

n const

=

=

=

J

aux

J

v const

=

J

i

d

Cog

d

i

-----------

2

i 2

=

m

v const

=

=

=

M

D

d

Cog

2000

-------------

F

aux

J

aux

α

+

=

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