Siemens SINUMERIK 840C - Manual (Page 971)

12 Functional Descriptions 09.95
12.19.5 Interpolation and compensation with tables
2. Example for calculating compensation curves
( IKA example 1 )
Machining of a contour with IKA
Y[mm]=100+160/3*COS[5/7*X[mm]])
from [X,Y]=[252,46.666] to [0,153.333]
Caution: This example does not take the tool offset
into account!
0. Preparation :
N0001 @40c K11 K2 K0 - Deactivate IKA 2
N0002 G0 X300 Y200 - Approach tool change point
N0003 R30=0 R31=0 - Error ID = 0
1. Structure of the table [ika3 data] :
N0005 @40c K7 K1 K0 - Input quantities 1..13 :
N0010 @40c K7 K2 K30000 Angle 0, 30, ... , 360 degrees
N0015 @40c K7 K3 K60000 in units of 10**[-3] degrees
N0020 @40c K7 K4 K90000
N0025 @40c K7 K5 K120000
N0030 @40c K7 K6 K150000
N0035 @40c K7 K7 K180000
N0040 @40c K7 K8 K210000
N0045 @40c K7 K9 K240000
N0050 @40c K7 K10 K270000
N0055 @40c K7 K11 K300000
N0060 @40c K7 K12 K330000
N0065 @40c K7 K13 K360000
N0070 @40c K8 K1 K0 - output quantities 1..13 :
N0075 @40c K8 K2 K5000 Sine [0], ... , Sine [360 degrees]
N0080 @40c K8 K3 K8660 in units of 10**[-4]
N0085 @40c K8 K4 K10000 SIN=1 -> 10000=10 mm
N0090 @40c K8 K5 K8660
N0095 @40c K8 K6 K5000
N0100 @40c K8 K7 K0
N0105 @40c K8 K8 K-5000
N0110 @40c K8 K9 K-8660
N0115 @40c K8 K10 K-10000
N0120 @40c K8 K11 K-8660
N0125 @40c K8 K12 K-5000
N0130 @40c K8 K13 K0
2. Start and end pointer [ika2 data] :
N0135 @40c K5 K1 K1 - Curve 1 uses points 1...13
N0140 @40c K6 K1 K13
N0145 @40c K55 K1 K-1 - Calculate curve 1
N0146 @30c R30 K55 K1 - [a] read error byte [> R30]
N0147 @111 R30 K0 K150 - [b] case statement for R30 :
K1 K281 Jump list for R30=1 .. 4 [error]
K2 K282 otherwise continue [R30=0] at N150;
K3 K283 scan [a] is repeated as long as
K4 K284 R30 =-1 or R30=-127
K127 K-146
K-1 K-146
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SINUMERIK 840C (IA)